5x=40x^-(1/2)

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Solution for 5x=40x^-(1/2) equation: 



5x=40x^-(1/2)

We move all terms to the left:

5x-(40x^-(1/2))=0

We add all the numbers together, and all the variables

5x-(40x^-(+1/2))=0

We multiply all the terms by the denominator


5x*2))-(40x^-(+1=0

Wy multiply elements

10x^2+1=0

a = 10; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·10·1
Δ = -40
Delta is less than zero, so there is no solution for the equation

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